Many students make the mistake of rushing to the answer. In the Beer and Johnston methodology, the "Solution" is the work shown, not just the final number.
The y-component of the resultant force $R$ is: $R_y = F_1y + F_2y = 50 + 129.90 = 179.90 \text N$ Many students make the mistake of rushing to the answer
The y-component of $F_1$ is: $F_1y = F_1 \sin 30^\circ = 100 \sin 30^\circ = 50 \text N$ the "Solution" is the work shown