Before we dive into formulas, we must understand why we need derivatives.
v=dxdt=ddt(3t2+5t+2)v equals d x over d t end-fraction equals d over d t end-fraction open paren 3 t squared plus 5 t plus 2 close paren Using the power rule:
$y = 5x^3$. $$ \fracdydx = 5 \cdot \fracddx(x^3) = 5 \cdot 3x^2 = 15x^2 $$
[ \fracdydx = \fracdydu \cdot \fracdudx ] Acceleration ( a = \fracdvdt = \fracdvdx \cdot \fracdxdt = v \fracdvdx )
Derivatives Class 11 Physics -
Before we dive into formulas, we must understand why we need derivatives.
v=dxdt=ddt(3t2+5t+2)v equals d x over d t end-fraction equals d over d t end-fraction open paren 3 t squared plus 5 t plus 2 close paren Using the power rule:
$y = 5x^3$. $$ \fracdydx = 5 \cdot \fracddx(x^3) = 5 \cdot 3x^2 = 15x^2 $$
[ \fracdydx = \fracdydu \cdot \fracdudx ] Acceleration ( a = \fracdvdt = \fracdvdx \cdot \fracdxdt = v \fracdvdx )